+0  
 
0
51
1
avatar

Find the perimeter of a trapezoid with vertices located at L(1,4), M(-2,0), N(7,0), and Q(3,4).  Round your answer to the nearest hundredth when necessary.

 Mar 1, 2021
 #1
avatar+118069 
+1

LM  =sqrt  [ 4^2  + (1 - -2)^2 ]  =  sqrt  [ 4^2 + 3^2]  =  sqrt (25) =  5

MN  =  sqrt  [ (7 - - 2)^2  ]  =  sqrt [ 9^2 ]  =  9

NQ  = sqrt   [ ( 7-3)^2  + ( 4 - 0)^2 ] =  sqrt  [ 4^2 + 4^2  ]  =    4sqrt (2)

QL =  sqrt  [ ( 3 - 1)^2  + (4 - 4)^2   ]  =  sqrt [ 2^2]   =   2

 

Perimeter  =  5 + 9 + 2 + 4sqrt (2)   =    16  + 4sqrt (2)   units

 

cool cool cool

 Mar 1, 2021

66 Online Users

avatar
avatar
avatar
avatar