Find the perimeter of a trapezoid with vertices located at L(1,4), M(-2,0), N(7,0), and Q(3,4). Round your answer to the nearest hundredth when necessary.
+128475 LM =sqrt [ 4^2 + (1 - -2)^2 ] = sqrt [ 4^2 + 3^2] = sqrt (25) = 5
MN = sqrt [ (7 - - 2)^2 ] = sqrt [ 9^2 ] = 9
NQ = sqrt [ ( 7-3)^2 + ( 4 - 0)^2 ] = sqrt [ 4^2 + 4^2 ] = 4sqrt (2)
QL = sqrt [ ( 3 - 1)^2 + (4 - 4)^2 ] = sqrt [ 2^2] = 2
Perimeter = 5 + 9 + 2 + 4sqrt (2) = 16 + 4sqrt (2) units
