Find the intersection points of the circles (x - 2)^2 + (y - 3)^2 = 9 and (x - 2)^2 + (y + 4)^2 = 16.
+36916 Fully expand the two equations and equate them (first one is x^2-4x+4+y^2-6y+9 - 9 = 0 ) and you will find it boils down to this
4-6y = 4 + 8y
14y = 0
y = 0 then sub this into either one of the equations to find the value of x = 2
One point of intersection: 2,0
