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Find the intersection points of the circles (x - 2)^2 + (y - 3)^2 = 9 and (x - 2)^2 + (y + 4)^2 = 16.

 Jul 4, 2020
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Fully expand the two equations and equate them  (first one is    x^2-4x+4+y^2-6y+9 - 9 = 0  ) and you will find it boils down to this

4-6y = 4 + 8y

14y = 0

y = 0       then sub this into either one of the equations  to find the value of x = 2

 

One point  of intersection:   2,0   

 Jul 4, 2020

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