Find the point on the line 3x + 4y = 5 that is closest to the origin. I tried solving this, but I couldn't.
+36916 Formula for distance from a point to a line :
3x+4y-5 = 0 (your line) point (0, 0 ) means x1=0 y1=0
a = 3 b = 4 c = -5
d=|ax1+by1+c| / sqrt(a2+b2) thry this ....let us know what you find !
