Let $a$ and $b$ be real numbers, where $a < b$, and let $A = (a,a^2)$ and $B = (b,b^2)$. The line $\overline{AB}$ (meaning the unique line that contains the point $A$ and the point $B$) has slope $2$. Find $a + b$.
Slope = [ b^2 - a^2 ] / [ b - a] = [ (b + a) (b -a) ] / (b - a) = 2
So
a + b = 2
+136 
