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Find the radius of a circle with the equation:
x2 + y2 – 18x – 14y + 120 = 0

 Apr 14, 2022
 #1
avatar+326 
+3

\(x^2+y^2-18x-14y+120=0\)

 

Converting to standard circle equation:

 

\(\left(x−a\right)^2+\left(y−b\right)^2=r^2\)

 

\(\left(x-9\right)^2+\left(y-7\right)^2=\left(\sqrt{10}\right)^2\)

 

\(center: (9, 7)\)

 

\(radius: \sqrt{10}\)

 

-Vinculum

 

smileysmileysmiley

 Apr 14, 2022
edited by Vinculum  Apr 14, 2022
 #2
avatar
-2

bruh, your just copying from another question

Guest Apr 14, 2022
 #4
avatar+326 
+2

They are all the same because they all use a similar method:

It is the quickest way to solve it!!!

 

smiley

 

I hope you have a great day!

Vinculum  Apr 14, 2022
 #3
avatar+122390 
+2

We can write

 

x^2  -18x  + y^2  -14y  =   -120               complete the square on  x and  y

 

x^2 -18x + 81  + y^2  -14y + 49  =  -120 + 81 + 49         factor and  simplify

 

(x - 9)^2 + ( y -7)^2  = 10

 

Center = (9, 7)

 

Radius  = sqrt (10)

 

cool cool cool

 Apr 14, 2022

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