Line $\ell_1$ represents the graph of $3x + 2y = -14 - 8x + 5y$. Line $\ell_2$ passes through the point $(5,-6)$, and is perpendicular to line $\ell_1$. Write the equation of line $\ell_2$ in the form $y=mx +b$.
Rearrange L1 as
-3y = -11x - 14
Slope of L1 = 11/3
Slope of a perpendicular line = -3/11
L2 equation L
y = (-3/11) (x - 5) - 6
y = (-3/11)x + 15/11 - 6
y = (-3/11)x + 15/11 - 66/11
y = (-3/11)x - 51/11
+2115 
