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avatar+1748 

Line $\ell_1$ represents the graph of $3x + 2y = -14 - 8x + 5y$.  Line $\ell_2$ passes through the point $(5,-6)$, and is perpendicular to line $\ell_1$.  Write the equation of line $\ell_2$ in the form $y=mx +b$.

 May 17, 2024
 #1
avatar+129493 
+1

Rearrange L1  as

-3y = -11x - 14

Slope of L1   = 11/3

Slope of a perpendicular line  = -3/11

 

L2  equation L

 

y = (-3/11) (x - 5) - 6

 

y = (-3/11)x + 15/11 - 6

 

y = (-3/11)x + 15/11 - 66/11

 

y = (-3/11)x - 51/11

 

cool cool cool

 May 17, 2024

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