In terms of pi, what is the area of the circle defined by the equation 2x^2+2y^2+10x-6y-48=0
+36916 Arrange in standard circle form to find r^2 first divide by 2
x^2 + 5x + y^2 - 3y = 48 complete the square for x and y
(x+ 2.5)^2 + ( y - 1.5)^2 = 48 + 6.25 + 2.25
r^2 = 56.5 pi r^2 = area = 56.5 pi units2
+2401 Nice. :))
I got the same answer, but I think you forgot to divide the 48 by 2.
x^2 + 5x + y^2 - 3y = 24
(x + 2.5)^2 + (y - 1.5)^2 = 24 + 1.5^2 + 2.5^2
(x + 2.5)^2 + (y - 1.5)^2 = 32.5
area = 32.5pi
=^._.^=
+36916 Arrange in standard circle form to find r^2 first divide by 2
x^2 + 5x + y^2 - 3y = 24 complete the square for x and y
(x+ 2.5)^2 + ( y - 1.5)^2 = 24 + 6.25 + 2.25
r^2 = 32.5 pi r^2 = area = 32.5 pi units2 *** edited *** to fix error noted by catmg !
