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# coordinates

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In terms of pi, what is the area of the circle defined by the equation  2x^2+2y^2+10x-6y-48=0

May 14, 2021

#1
+32833
+2

Arrange in standard circle form to find r^2     first divide by 2

x^2 + 5x     + y^2  - 3y   = 48      complete the square for x and y

(x+ 2.5)^2   + ( y - 1.5)^2   = 48 + 6.25 + 2.25

r^2 = 56.5                        pi r^2 = area = 56.5 pi units2

May 14, 2021
#2
+1940
+1

Nice. :))

I got the same answer, but I think you forgot to divide the 48 by 2.

x^2 + 5x + y^2 - 3y = 24

(x + 2.5)^2 + (y - 1.5)^2 = 24 + 1.5^2 + 2.5^2

(x + 2.5)^2 + (y - 1.5)^2 = 32.5

area = 32.5pi

=^._.^=

catmg  May 14, 2021
#3
+32833
+1

Arrange in standard circle form to find r^2     first divide by 2

x^2 + 5x     + y^2  - 3y   = 24        complete the square for x and y

(x+ 2.5)^2   + ( y - 1.5)^2   = 24 + 6.25 + 2.25

r^2 = 32.5                        pi r^2 = area = 32.5 pi units2       *** edited ***   to fix error noted by  catmg !

ElectricPavlov  May 14, 2021
#4
+32833
+1

YEP...I missed that !   THANX     I edited my answer .....   ~ EP

ElectricPavlov  May 14, 2021