Let line 1 be the graph of 5x+8y=-9. Line 2 is perpendicular to line 1 and passes through the point (10,-12). If line 2 is the graph of the equation y=mx+b, then find. m+b
+23252 Line 1: 5x + 8y = -9
8y = -5x - 9
y = (-5/8)x - 9/8
The slope of this line is -5/8.
This means that the slope of any line perpendicular to it is 8/5.
Line 2: point = (10, -12) slope = 8/5
Point-slope form for a line: y - y1 = m(x - x1)
y - -12 = (8/5)(x - 10)
y + 12 = (8/5)(x - 10)
5y + 60 = 8x - 80
5y = 8x - 140
y = (8/5)x - 28
Can you finish?
