What is the x-coordinate of the point on the x-axis that is equidistant from points (-2, 0) and \((0,6)\)?
What is the x-coordinate of the point on the x-axis?
Hello Guest!
\(m_{g(x)}=\frac{y_2-y_1}{x_2-x_1}=\frac{6-0}{0+2}\\ m_{g(x)}=3\\ m_{f(x)}=-\frac{1}{3}\\ P_{center}(-1,\ 3)\)
\(f(x)=0=-\frac{1}{3}(x+1)+3\\ \frac{1}{3}(x+1)=3\\ \color{blue}x=8\)
The x-coordinate of the point on the x-axis is 8.
!