In terms of pi, what is the area of the circle defined by the equation 2x^2+2y^2+10x-6y-48=x^2+y^2-2x+4y-10
In terms of pi, what is the area of the circle defined by the equation 2x^2+2y^2+10x-6y-48=x^2+y^2-2x+4y-10
2x2 + 2y2 + 10x – 6y – 48 = x2 + y2 – 2x + 4y – 10
Combine like terms x2 + y2 + 12x – 10y = – 10
Rearrange & add parentheses (x2 + 12x ) + (y2 – 10y ) = – 10
in preparation to complete sqs
Complete the squares. Anything (x2 + 12x + 36) + (y2 – 10y + 25) = – 10 + 36 + 25
added to the left side, has to be
added to the right side also.
Simplify (x + 6)2 + (y – 5)2 = 51
The equation of a circle is (x – h)2 + (y – k)2 = r2
where x and y locate the
center and r is the radius.
So r2 of this circle is 51. Area of a circle is π r2. So the area is 51 π.
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