What is the x-coordinate of the point on the x-axis that is equidistant from points A(-2,4) and B(0,18)?
Let the point be ( x , 0)
Using the square of the distance formula
( x - -2)^2 + (4 - 0)^2 = ( 0 - x)^2 + (18 - 0 )^2 simplify
x^2 + 4x + 4 + 16 = x^2 + 324
4x + 20 = 324
4x = 324 - 20
4x = 304
x = 76
The point is (76, 0 )
