Find the equation of the line that passes through the points (-2,1) and (-3,3). Write your answer in the form y = mx + b.
+1223 \(\text{slope} = m = \frac{3 - 1}{-3 - (-2)} = -2\)
Plug in one of the points, such as (-2, 1).
\(y=mx+b\)
\(1 = -2(-2) + b\)
\(-3= b\)
Therefore, the equation is \(\boxed{y = -2x -3}\).
