Points A(0, 0) B(6, 0), C(6, 10) and $D(0, 10)$ are vertices of rectangle ABCD, and E is on segment CD at (1, 10). What is the ratio of the area of triangle ADE to the area of quadrilateral ABCE? Express your answer as a common fraction.
What is the ratio of the area of triangle ADE to the area of quadrilateral ABCE?
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\(A_{ADE}=\frac{10\cdot 1}{2}=5\\ A_{ABCE}=6\cdot 10-5=55\\ \color{blue}\frac{A_{ADE}}{A_{ABCE}}=\frac{5}{55}=\frac{1}{11}\)
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