+0  
 
0
32
1
avatar

A point (x,y) is a distance of 6 units from the x-axis. It is a distance of sqrt(58) units from the point (8,3). It is a distance sqrt(n) from the origin,. Given that x < 8, what is n?

 Jul 22, 2022
 #1
avatar+124524 
+1

Costruct  a circle with a center of  (8,3)  and a  radius of  sqrt 58

 

The equation of this  circle   is

 

(x - 8)^2  + ( y  - 3)^2 =  58

 

Our point must be on this  circle and is 6 units from  the x axis (y coord of the point  =  6)

 

So

 

(x - 8)^2  + (6 -3)^2    =  58

 

(x - 8)^2  + 9 = 58

 

(x - 8)^2  =  49

 

x - 8  =  -sqrt (49)

 

x =  8 - 7    = 1

 

n = 1^2  + 6^2 =    37

 

cool cool cool

 Jul 22, 2022

15 Online Users

avatar
avatar
avatar