Let line 1 be the graph of 5x+8y=-9. Line 2 is perpendicular to line 1 and passes through the point (10,-10). If line 2 is the graph of the equation y=mx+b, then find m+b.
Find m+b.
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\(5x+8y=-9\\ \color{blue}y_1=-\frac{5}{8}\cdot x-\frac{9}{8}\)
\(m=\frac{8}{5}\\ y_2=m(x-x_2)+y_2\\ y_2=\frac{8}{5}(x-10)-10\\ \color{blue}y_2=\frac{8}{5}x-26\\ y_2=mx\ +\ b \)
\(m+b=-24.4\)
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