What is the x-coordinate of the point on the x-axis that is equidistant from points A(2,0) and B(0,6)?
On the x axis = (a, 0)
Now we can use the distance formula.
(a-2)^2 + (0-0)^2 = (a-0)^2 + (0-6)^2
a^4 - 4a + 4 = a^2 + 36
-4a = 32
a = -8
I hope that's right. :)
=^._.^=