Line $l_1$ represents the graph of 3x + 4y = -14. Line $l_2$ passes through the point $(-5,-7)$, and is perpendicular to line $l_1$. If line $l_2$ represents the graph of y=mx +b, then find m+b.
If line $l_2$ represents the graph of y=mx +b, then find m+b.
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P ( -5, -7)
\(f(x)=-\frac{3}{4}x-3.5\)
\(m_1=-\frac{3}{4}\\ m_2=\frac{4}{3}\)
\(g(x)=m(x-x_P)+y_P\)
\(g(x)=\frac{4}{3}(x+5)-7\)
\(g(x)=\frac{4}{3}x-\frac{1}{3}\)
\(y=mx+b\)
\(m+b=1\)
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