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Line $l_1$ represents the graph of 3x + 4y = -14. Line $l_2$ passes through the point $(-5,-7)$, and is perpendicular to line $l_1$. If line $l_2$ represents the graph of y=mx +b, then find m+b.

 Dec 27, 2021
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 If line $l_2$ represents the graph of y=mx +b, then find m+b.

 

Hello Guest!

 

P ( -5, -7)

\(f(x)=-\frac{3}{4}x-3.5\)

\(m_1=-\frac{3}{4}\\ m_2=\frac{4}{3}\)

\(g(x)=m(x-x_P)+y_P\)

\(g(x)=\frac{4}{3}(x+5)-7\)

\(g(x)=\frac{4}{3}x-\frac{1}{3}\)

     \(y=mx+b\)

 

\(m+b=1\)

laugh  !

 Dec 28, 2021
edited by asinus  Dec 28, 2021

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