A line passes through the points $A,$ $B,$ and $C.$ If $A = (-2,-4),$ $B = (-3,12),$ and $C = (4,y),$ then find $y.$
A(-2,-4), B(-3,12), C(4,y) find y.
\(m= \dfrac{y_B-y_A}{x_B-x_A}=\dfrac{12-(-4)}{-3-(-2)}=-16\\ y=m(x-x_A)+y_A=-16(x-(-2))+(-4)=-16x-32-4\\ y=-16x-36\\ y_C=-16x_C-36=-16\cdot 4-36\\ \color{blue}y_C=-100\)
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+1234 
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