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Find the equation of the line in slope intercept form that is perpendicular to 2x-3y-12=0 and passes through the point (-3, 5). show your work

 Jan 30, 2021

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3y = 2x-12

y = 2/3 x - 4      slope = 2/3    perpindicular = -1 / 2/3 =   3/2

 

Point slope form of your new line     y-5 = 3/2 ( x+3)

 Jan 30, 2021
 #1
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Best Answer

3y = 2x-12

y = 2/3 x - 4      slope = 2/3    perpindicular = -1 / 2/3 =   3/2

 

Point slope form of your new line     y-5 = 3/2 ( x+3)

Guest Jan 30, 2021

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