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Let line L_1 be the graph of 5x + 8y = -9. Line L_2 is perpendicular to line L_1 and passes through the point (10,-10). If line L_2 is the graph of the equation y=mx +b, then find m+b.

 May 28, 2021
 #1
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We  first  need to  find  the  slope of L1

 

5x  +  8y   =  -9

8y =  -5x   - 9

y  = ( -5/8)x - 9/8

 

The slope  =  -5/8

L2  will  have  a negative reciprocal  slope =   8/5

 

Since L2  passes through (10, -10)  we  have

 

y  = (8/5) ( x - 10)   - 10

 

y =  (8/5)x  -  16  -   10

 

y = (8/5)x  -  26

 

m   +  b   =      8/5  -  26   =  -122/5

 

 

cool cool cool

 May 28, 2021

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