In terms of pi, what is the area of the circle defined by the equation 2x^2+2y^2+10x-6y-48=x^2+y^2-2x+4y-10
In terms of pi, what is the area of the circle defined by the equation 2x^2+2y^2+10x-6y-48=x^2+y^2-2x+4y-10
2x2 + 2y2 + 10x – 6y – 48 = x2 + y2 – 2x + 4y – 10
x2 + y2 + 12x – 10y – 38 = 0
complete the squares (x2 + 12x ) + (y2 – 10y ) = 38
(x2 + 12x + 36) + (y2 –10y + 25) = 38 + 36 + 25
(x + 6)2 + (y – 5)2 = 99
equation for all circles is (x – h)2 + (y – k)2 = r2 <— (r2 is the radius squared)
Area = π r2
Area = π • 99
Area = 99 π
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