The graphs of 2y + x + 3 = 0 and 3y + ax + 2 = y + 2x are perpendicular. Solve for a.
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\(y=-\dfrac{x}{2}-1.5\ |\ \color{blue}m_1=-\frac{1}{2}\\ 2y + (a-2)x + 2 = 0\\ y+\dfrac{(a-2)x}{2}+1=0 \)
\(m_2=-\dfrac{1}{m_1}=2\\ \dfrac{a-2}{2}=2\)
\(a=-2\)
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