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cos(−θ)=−√2/5 sin. θ>0

 

What is the value of sinθ?

 

−√23/5

√23/5

√2/5

−√2/5

 Dec 6, 2017
edited by Guest  Dec 6, 2017
 #1
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0

cos(−θ)=−√2/5 sin. θ>0

 

(−θ) =cos^-1(-√2/5)

(θ) =106.43 Degrees

sin(106.43) =√23/5

 Dec 6, 2017
 #2
avatar+94295 
+1

Here's another way

sin  = y / r

 

x  = - √2

y =  ???

r  = 5

 

y  =   +√ [ r^2 - x^2 ]

y = + √ [ 5^2 - (-√2)^2 ]      

y = + √ [25 - 2]

 

y = √23

 

So 

 

sin  = √23 / 5

 

 

 

cool cool cool

 Dec 6, 2017

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