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-cos(300) = cos theta

 Jun 11, 2014

Best Answer 

 #1
avatar+130514 
+5

I'm assuming you want to find an angle with the same value as -cos(300)

cos(300) = 1/2   ....so ...-cos(300) = -1/2

So, you're looking for an angle with a cosine value of -1/2

This occurs at 120 degrees and at 240 degrees

The general answers would be

120 + n360   and   240 + n360          where n is an integer

 Jun 11, 2014
 #1
avatar+130514 
+5
Best Answer

I'm assuming you want to find an angle with the same value as -cos(300)

cos(300) = 1/2   ....so ...-cos(300) = -1/2

So, you're looking for an angle with a cosine value of -1/2

This occurs at 120 degrees and at 240 degrees

The general answers would be

120 + n360   and   240 + n360          where n is an integer

CPhill Jun 11, 2014

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