cos CAB if AC= 4 and BC= 3

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Guest Sep 15, 2014

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This seems to refer to the well-known right-angled triangle with sides BC = 3, AC = 4, AB = 5, in which case cos(CAB) = 4/5 (=0.8)

Alan Sep 15, 2014

Alan · Answer 1 · 2014-09-15T03:10:22

This seems to refer to the well-known right-angled triangle with sides BC = 3, AC = 4, AB = 5, in which case cos(CAB) = 4/5 (=0.8)