My textbook says that theta = ~1.02 radians. The equation is on the left. How did they arrive at that answer?
θ is the angle whose cosine is 3*√(6)/14 so
θ = cos-1(3*√(6)/14)
$${\mathtt{theta}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{6}}}}}{{\mathtt{14}}}}\right)} \Rightarrow {\mathtt{theta}} = {\mathtt{58.339\: \!117\: \!225\: \!405^{\circ}}}$$
180° is pi radians, so in radians we have
$${\mathtt{theta}} = {\frac{{\mathtt{58.339\: \!117\: \!225\: \!405}}{\mathtt{\,\times\,}}{\mathtt{\pi}}}{{\mathtt{180}}}} \Rightarrow {\mathtt{theta}} = {\mathtt{1.018\: \!209\: \!678\: \!290\: \!256\: \!2}}$$
or θ ≈ 1.02 radians
θ is the angle whose cosine is 3*√(6)/14 so
θ = cos-1(3*√(6)/14)
$${\mathtt{theta}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{6}}}}}{{\mathtt{14}}}}\right)} \Rightarrow {\mathtt{theta}} = {\mathtt{58.339\: \!117\: \!225\: \!405^{\circ}}}$$
180° is pi radians, so in radians we have
$${\mathtt{theta}} = {\frac{{\mathtt{58.339\: \!117\: \!225\: \!405}}{\mathtt{\,\times\,}}{\mathtt{\pi}}}{{\mathtt{180}}}} \Rightarrow {\mathtt{theta}} = {\mathtt{1.018\: \!209\: \!678\: \!290\: \!256\: \!2}}$$
or θ ≈ 1.02 radians