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What is the area of Figure ABCD?

A trapezoid ABCD is drawn with length of parallel sides AB and CD equal to 14 inches and 18 inches, respectively. The length of one of the non-parallel sides BC is 7 inches. Side BC is perpendicular to DC. A perpendicular line drawn from A to side CD meets CD at E.

 

LIke do I turn the 18in into 15in for the rectangle and 3in for the tiny triangle 

 Mar 22, 2019
 #1
avatar+233 
+2

If I'm reading this correct, that last bit of information about E is unneccesary. The area of a trapezoid is the average of the bases times the height. Since BC is perpendicular to the bases, (AB and DC) it is the height. To find the average of the bases, add them together and divide them by how many factors there are. So \(A = \frac {14 + 18}{2} \cdot 7 = 16 \cdot 7 = 112\).

 

Hope this helps!

 Mar 22, 2019
 #2
avatar+2068 
+5

Thanks LagTho you are AWSOME 

Nickolas  Mar 23, 2019
 #3
avatar+1264 
+4

You have been asking very similar questions...are you grasping the concept were teaching???

HiylinLink  Mar 23, 2019
 #4
avatar+2068 
+5

Talk thread is closed unless Lagtho wants to respond

Nickolas  Mar 23, 2019
 #5
avatar+2068 
+5

Yes!!!!!!!!!!!!!!

Nickolas  Mar 23, 2019
 #6
avatar+233 
+2

Wow rude. Glad I could help tho

LagTho  Mar 23, 2019
 #7
avatar+2068 
+3

He is my Brother any ways so we have those fights

Nickolas  Mar 23, 2019

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