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https://web2.0calc.com/questions/please-help_97551

 Jun 16, 2021
 #1
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I will go and answer it now!

 Jun 17, 2021
 #2
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+2

The roots of the cubic are 5, -12, and 9, and you would find (x, y, z), and from that x+y, by assigning a permutation of the roots to (3x, 5y, -6z). Three numbers can be permuted in 6 different ways, so there are 6 different assignments:

(3x, 5y, - 6z)=(9, 5, -12)

                   =(9, -12, 5)

                   = (5, 9, -12)

                   =(5, -12, 9)

                   = (-12, 5, 9)

                   =(-12, 9, 5)

You would find 6 values for x +y this way, and I think they turn out to be distinct.

 Jun 17, 2021
 #3
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Thanks guest but next time please answer on the original post and just leave a little note here saying that you have done so.

Melody  Jun 22, 2021

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