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Could you help me find the answer to (y^-5)^10y^10?

 Feb 2, 2015

Best Answer 

 #2
avatar+118587 
+5

$$\\(y^{-5})^{10}y^{10}
=y^{-50}y^{10}
=y^{-40}
=\frac{1}{y^{40}}$$

.
 Feb 3, 2015
 #2
avatar+118587 
+5
Best Answer

$$\\(y^{-5})^{10}y^{10}
=y^{-50}y^{10}
=y^{-40}
=\frac{1}{y^{40}}$$

Melody Feb 3, 2015

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