Two particles are separated by a distance of 0.3525977 m. Charge 1 has a charge of 0.0000764 C. Particle 2 has a charge of 0.0000745. What is the force between them?
Two particles are separated by a distance of 0.3525977 m. Charge 1 has a charge of 0.0000764 C. Particle 2 has a charge of 0.0000745. What is the force between them?
Use the firmula: F=[k. Q. q] / r^2
F=[8.99 X 10^9 X .0000764 X .0000745] / .3525977^2
F=411.58 newtons-the force between the two charged particles.
