How many positive five digit numbers have a 1, 3, 7 or 5 in them?
Counting the number of positive 5-digit numbers that don't contain an odd digit =
4 choices for the 1st digit * 4 choices for each of the other 5 digits =
4 * 5^4 = 2500
So the number of positive 5-digit numbers containing at least 1 odd digit = (90,000 - 2500) =
87500
EDIT TO CORRECT A MISTAKE !!!!