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Five couples were at a party. If each person shook hands exactly once with everyone, how many handshakes were exchanged? (Note: One obviously doesn't shake hands with oneself.)

 Jul 1, 2022
 #1
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For N people.....the number of handshakes = 

 

(N) ( N-1)  / 2

 

So

 

(5) (5 - 1)   /2   =

 

( 5 * 4)  / 2  =

 

10 handshakes

 

cool cool cool

 Jul 1, 2022
 #2
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IF couple 1 names A and so on, 

 

A-B,C,D,E (4)

 

B-C,D,E (3)

 

C-D,E (2)

 

D-E (1)

 

1+2+3+4=10

 

Ans:10

 Jul 2, 2022

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