Two boys and three girls are going to sit around a table with 5 different chairs. If the two boys want to sit next to Jill, in how many possible ways can they be seated?
+874 Let the two boys and Jill be one: There are $\binom{3}{2} = 3$ possibilities to permute them.
Then there are $5-3 + 1 = 3$ people. There is $\binom{5}{3} = 10.$
the answer is $10\cdot 3 = \boxed{30}$
