+0  
 
0
40
1
avatar

In how many ways can 8 people A, B, C, D, E, F, G and H be seated in a row if persons A and B must not sit next to each other?

 Feb 23, 2020
 #1
avatar
0

There are 8*6 ways of seating A and B, then 6! ways of seating the other 6 people, so the answer is 8*6*6! = 34560.

 Feb 23, 2020

37 Online Users

avatar
avatar
avatar
avatar
avatar
avatar
avatar