An ordinary 6-sided die has a number on each face from 1 to 6 (each number appears on one face). How many ways can I paint two faces of a die blue, so that the product of the numbers on the painted faces isn't equal to 2?
The number of possible outcomes = C(6,2) = 15
The only way a "2" can be achieved is by painting face "1" and face "2" both blue
So......14 ways
