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Find the number of solutions to a + 2b + 3c = 6 in nonnegative integers.

 Oct 12, 2022
 #1
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I believe there are seven solutions to this. These are listed below:

 

Each three numbers inside parentheses correspond to the values of a, b, and c in that order in a specific solution:

(0, 0, 2) (0, 3, 0) (1, 1, 1) (2, 2, 0) (3, 0, 1) (4, 1, 0) (6, 0, 0)

 Oct 12, 2022

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