+0  
 
0
164
1
avatar

In how many ways can you distribute 10 indistinguishable boxed among 8 distinuishable boxes, if at least one of the boxes must be empty?

 Dec 21, 2022
 #1
avatar
0

Give this a try !

 

[10 + 8 - 1] C [8 - 1] ==17 C 7 ==19,448 ways - this is based on the assumption that ALL distributions are equally likely, including counting of empty boxes.

 Dec 21, 2022

2 Online Users

avatar