Four numbers are chosen at random from {1, 2, 3, ..., 10}. What is the probability that neither 2 nor 9 is chosen?
Not POSITIVE answer
6 choices out of 10 6/10
then 9 numbers left 5 choices out of 9 5/9
then 8 numbers left 4 choices out of 8 4/8
then 7 numbers left 3 choices out of 7 3/7
6/10 * 5/9 * 4/8 * 3/7 = 1/14