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Four numbers are chosen at random from {1, 2, 3, ..., 10}.  What is the probability that neither 2 nor 9 is chosen?

 Sep 2, 2020
 #1
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Not POSITIVE answer

 

6 choices out of 10      6/10

  then 9 numbers left    5 choices out of 9   5/9

      then 8 numbers left    4 choices out of 8    4/8

         then 7 numbers left    3 choices out of 7   3/7

 

6/10 * 5/9 * 4/8 * 3/7 = 1/14

 Sep 3, 2020

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