How many three digit odd numbers can be formed from the digits 1, 2, 3, 4 and 5, if no digits are to be repeated?
The answer would be:
m x n x p = 5 x 4 x 3 = 60
So the answer would be 60
There are \(5 \times 4 \times 3 = 60\) ways to choose without any restrictions.
Note that of these integers, exactly \(3 \over 5\)th of them are odd because there are 5 choices for the final digit, 3 of which, are odd.
This means that there is \({3 \over 5} \times 60 = \color{brown}\boxed{36}\) numbers.