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The number of diagonals in a certain regular polygon is equal to ten times the number of sides. How many sides does this polygon have?

 Apr 19, 2021

Best Answer 

 #1
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Number of diagonals of a polygon     n ( n-3)/2

 

n(n-3)/2 = 10n

n^2 -3n = 20n

n^2 -23n= 0

n ( n- 23)  = 0        n = 0  (throw out)     or     n = 23

 Apr 19, 2021
 #1
avatar+31353 
+2
Best Answer

Number of diagonals of a polygon     n ( n-3)/2

 

n(n-3)/2 = 10n

n^2 -3n = 20n

n^2 -23n= 0

n ( n- 23)  = 0        n = 0  (throw out)     or     n = 23

ElectricPavlov Apr 19, 2021

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