Can anyone help plz?
A debate team consists of 5 freshmen and 4 sophomores. (Everyone is distinguishable.) In how many ways can they stand in line, so at least two of the sophomores are standing next to each other, and at least two of the freshmen are at the ends of the line?
+118679 there are 5*4 =20 ways to chose the 2 freshmem for the end of the line.
Now there are 7! ways to order rest. = 5040 ways
But how many of those 7! ways do NOT have any 2 sophomores standing together.
the order would have to be SFSFSFS there are 4!*3! = 144ways
5040-144 = 4896
4896*20 = 97920 ways
