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Find the number of positive integers that satisfy both the following conditions:

Each digit is a 1 or a 2

The sum of the digits is 3

 Mar 2, 2023
 #1
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I could only think of three, 12, 21, and 111. Not sure if there's more though..

 Mar 2, 2023
 #2
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If each digit has to be 1 or 2 and they have to add up to 3, there are only a few ways we can have this number. The first is 111 (1+1+1 = 3), the second is 21 (2+1 = 3), and finally the third is 12 (1+2 = 3). your final answer is 111,21, and 12
hope this helps!
 Mar 2, 2023

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