Miyu is giving out 9 identical chocolates to her 7 friends, including Dhruv. All possible distributions are equally likely. What is the probability that Dhruv gets exactly 2 chocolates?
Miyu is giving out 9 identical chocolates to her 7 friends, including Dhruv.
Put the friends in order Dhruv can go first but it really doesnet matter
There will be (9+7-1) C8 = 15C8 ways to distribute the chocolates
Now let Dvruv have her 2 chocs.
There are 6 friends left and 7 choc let so that makes 12C6 ways
So the likelyhood that Dvruv gets exactly 2 chocs is
12C6 divided by 15C8 = 924/6435 = 28/195 which is approx 14.35% chance