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How many ways are there to divide a red bracelet, a yellow bracelet, a green bracelet, and a black bracelet among 4 people if someone must receive exactly two bracelets?

 Nov 19, 2021
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Four people, 4 bracelets

One person gets exactly 2 so at least one person must get non.

 

2,1,1,0

4C2= 6 ways to choose the two

4 ways to chose the person who misses out

3 ways to chose the person to get 2,

2 ways to sort the rest

6*4*3*2 = 144 ways

  

2,2,0,0  

6 ways to pair the braclets, (normally you would halve this but I am thinking differently.)

4C2 ways to choose two people =6

6*6 = 36 ways

 

180 ways total, I think....

 Nov 20, 2021

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