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# Counting

0
42
5

How many different positive, six-digit integers can be formed using the digits 2, 2, 5, 6, 8 and 9?

Apr 14, 2022

#1
+1384
+1

$${6! \over 2!} = \color{brown}\boxed{360}$$

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Apr 14, 2022
#3
+122
-1

Gm builderboi

Kakashi  Apr 14, 2022
#4
+1384
+1

gm to you as well :)

BuilderBoi  Apr 14, 2022
#2
+326
+2

We have 6 numbers in the set "2, 2, 5, 6, 8, and 9", so we have 6! to find the different positive 6 digit integers that can be formed.

And we have two 2s... which means that we need to divide by 2!

That will give us: 6!/2! which is 360 different positive 6 digit numbers

Apr 14, 2022
#5
+122
-1

I had no clue how to do that bc i just forgot how to do some things i learn i the past

Apr 14, 2022