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Find the no. of permutations of letters a , b , c , d, e , f , g taken all at a time if "beg" pattern cannot appear in any word.

 Oct 15, 2020
 #1
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A, B, C, D, E, F, G =7 letters gives 7! =5040 permutations. Out of the 5040 permutations, there are 52 permutations with the word "BEG" in them. If you exclude those 52 permutations, then you have:

5040 - 52 =4,988 permutations.

 
 Oct 15, 2020
 #2
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Sorry, for the mistake in the number of "BEG" ! It is actually 120 permutations with the word "BEG" in them. I copied the wrong number. So, the total should be: 7! =5040 - 120 =4,920 permutations.

 
Guest Oct 15, 2020

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