How many three digit odd numbers can be formed from the digits 1, 2, 3, 4, and 5 if no digits are to be repeated?
Choose any of the odd integers for the units place = 3C1 = 3
Then we can choose any of the remaining four and permute them in 2 ways = 4P2 = 12
So
3 * 12 = 36 three-digit integers