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Find the number of solutions to a + 2b + 3c = 6 in nonnegative integers.

 Oct 10, 2022
 #1
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         a   b   c

1  = (6, 0, 0)
2  = (4, 1, 0)
3  = (2, 2, 0)
4  = (0, 3, 0)
5  = (3, 0, 1)
6  = (1, 1, 1)
7  = (0, 0, 2)

 Oct 10, 2022

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