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Plz help

 

A standard six-sided die is rolled 7 times.  You are told that among the rolls, there was one 1, two 2's, and three 4's.  How many possible sequences of rolls could there have been?  (For example, 5, 1, 2, 2, 4, 4, 4 is one possible sequence.  4, 1, 4, 4, 2, 1, 1 is one possible sequence.)

 Feb 7, 2023
 #1
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I first want to point out that the second example was incorrect becuase you need two 2's.

Honestly, I have no idea how to do this problem, Even Cphil is stuck on it: Proof at brainly if you copy paste this question

 Feb 7, 2023
 #2
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One six-sided die tossed 7 times should give you this many pemutations:

 

6^7 = 279,936 possible sequences.

 Feb 7, 2023

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