Counting

First, let's find the total number of ways Miyu and distribute the chocolates with no restrictions. 

According to the Stars and Bars Theorem, we have

$\binom{n + k - 1}{k - 1}$ where n is the identical items and k is the number of groups. 

Plugging in 8 and 5, we have

$\binom{8 + 5 - 1}{5 - 1} = \binom{12}{4} = 495$

Next, we must find the number of favorable outcomes. If Druv gets 6 chocolates, then there are 2 more chocolates for 4 other friends.

Using the same method, we have

$\binom{2 + 4 - 1}{4 - 1} = \binom{5}{3} = 10$

Now, we can write the equation

$P(\text{Dhruv gets 6}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{10}{495}$

So our answer is approximately 2.02%. 

Thanks! :)